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Q. what is maximum number of $100\, W , 200\, V$ lamps which can be connected in a circuit having a fuse wire of safe current $5 \, A$

KCETKCET 2022

Solution:

Since all the bulbs should get $200 \,V$, they are in parallel.
Resistance of each bulb
$= R = V ^{2} / p =200 \times 200 / 100=400 \,\Omega$
There fore $I=E / R_{p}$
$5=200 /(400 / n)$
$5=200 n / 400 .$
solving we get $n=10$.