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Q. What is $ {{K}_{c}} $ for the following equilibrium when equilibrium concentration of each substance is [8 $ [S{{O}_{2}}]=0.60M,\,\,[{{O}_{2}}]=0.82\,M $ and $ [S{{O}_{3}}]=1.90M $ ? $ 2S{{O}_{2}}(g)+{{O}_{2}}(g)\rightleftharpoons 2S{{O}_{3}}(g) $

VMMC MedicalVMMC Medical 2010

Solution:

For equation $ 2S{{O}_{2}}(g)+{{O}_{2}}(g)\rightleftharpoons 2S{{O}_{3}}(g) $ $ {{K}_{c}}=\frac{{{[S{{O}_{3}}]}^{2}}}{{{[S{{O}_{2}}]}^{2}}[{{O}_{2}}]} $ $ =\frac{{{[1.90\,M]}^{2}}}{{{[0.60M]}^{2}}[0.82M]} $ $ =12.229\,{{M}^{-1}} $ or $ 12.229\,L\,mo{{l}^{-1}} $