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Q. What is correct for 10 g of $CaCO_3$ ?

Some Basic Concepts of Chemistry

Solution:

$10\,g$ of $CaCO_{3}=\frac{10}{100}$
$=0.1\,g$ mol of $CaCO_{3}$
$=0\cdot1 \times 3$ g-atom of oxygen
$=0\cdot3\,g$ atoms of oxygen