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  4. What is(are) number(s) of unpaired electrons in the square planar, [ Pt ( CN )4]2- ion ?

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Q. What is(are) number(s) of unpaired electrons in the square planar, $\left[ Pt ( CN )_{4}\right]^{2-}$ ion ?

AMUAMU 2009

Solution:

In $\left[ Pt ( CN )_{4}\right]^{2-}, CN ^{-}$is a strong field ligand and outer configuration of Pt is $5 d^{9}, 6 s^{1}$.
Thus, outer configuration of $Pt ^{2+}$ is $5 d^{8}$.
$CN ^{-}$will cause pairing of electrons. Hence,
image
Therefore, number of unpaired electrons in $\left[ Pt ( CN )_{4}\right]^{2-}$ is zero.