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Q. What happens when magnesium is burnt in air and the products $X$ and $Y$ are treated with water ?
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$X$ $Y$ $P$ $Q$
(a)$\,\,$ $MgO\,\,$ $Mg(OH)_2\,\,$ $Mg(OH)_2\,\,$ $N_2\,\,$
(b)$\,\,$ $MgO\,\,$ $Mg_3N_2\,\,$ $Mg(OH)_2\,\,$ $NH_3\,\,$
(c)$\,\,$ $MgO\,\,$ $Mg_3N_2\,\,$ $Mg(OH)_2\,\,$ $N_2\,\,$
(d)$\,\,$ $MgO\,\,$ $MgCO_3\,\,$ $Mg(OH)_2\,\,$ $CO_2$

The s-Block Elements

Solution:

Magnesium reacts with air to form oxide and nitride. On reaction with water the oxide gives hydroxide and nitride gives hydroxide and ammonia.
$2Mg +O_2 \rightarrow \underset{(X)}{2MgO}$
$3Mg +N_2 \rightarrow \underset{(Y)}{Mg_3N_2}$
$MgO +H_2O \rightarrow \underset{(P)}{Mg(OH)_2}$
$MgO +H_2O \rightarrow \underset{(P)}{3Mg(OH)_2}+\underset{(Q)}{2NH_3}$