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Q. What entropy change is involved in the isothermal expansion of $5\, mol$ of ideal gas from a volume of $10\, L$ to $100\, L$ at $300\, K$?

Thermodynamics

Solution:

$\Delta S=n R \ln \frac{V_{2}}{V_{1}}=2.303 n R \log \frac{V_{2}}{V_{1}}$

$=2.303 \times 5 mol \times\left(8.314 JK ^{-1} mol ^{-1}\right) \log \frac{100 L }{10 L }=95.7 JK ^{-1}$