Q. What amount of bromine will be required to convert 2 g of phenol into 2,4,6-tribromo phenol ?
Solution:
94 g 480 g
$\because $ 94 g of phenol requires = 480 g $ Br_2$
$\therefore $ 2 g of phenol will require = $ \frac{ 480 }{ 94 } \times 2 $
= 10.22 g
