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  4. Wavelength of light emitted from second orbitto first orbit in a hydrogen atom is:

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Q. Wavelength of light emitted from second orbitto first orbit in a hydrogen atom is:

WBJEEWBJEE 2006

Solution:

$ \frac{1}{\lambda }=R\left( \frac{1}{{{1}^{2}}}-\frac{1}{{{2}^{2}}} \right) $ $ \Rightarrow $ $ \frac{1}{\lambda }=1.097\times {{10}^{7}}\times \frac{3}{4} $ $ \therefore $ $ \lambda =1.215\times {{10}^{-7}}m=1215\,\overset{\text{o}}{\mathop{\text{A}}}\, $