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  4. wavelength associated with a photon having energy 4.14 eV is

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Q. wavelength associated with a photon having energy 4.14 eV is

Dual Nature of Radiation and Matter

Solution:

$\lambda = \frac{hc}{E} = \frac{6.62 \times 10^{-34} \times 3 \times 10^8}{4.14 \times 1.6 \times 10^{-19}} m = 3000 \, A^{\circ} $ or $ \lambda = \frac{12400}{4.14} \, A^{\circ} $ nearly