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Q. Water rises upto a height $\text{h}$ in a capillary tube of certain diameter. This capillary tube is replaced by a similar tube of half the diameter. Now water will rise to a height of

NTA AbhyasNTA Abhyas 2020

Solution:

From capillary tube experiment, We know that
$\text{h}=\frac{2 \text{Scos} \theta }{\text{r} \text{ρ} \text{g}}\text{i.e.}\text{h} \propto \frac{1}{\text{r}}$
$\therefore \frac{\text{h}^{'}}{\text{h}} = \frac{\text{r}}{\text{r/} 2} = 2 \text{or} \text{h}^{'} = 2 \text{h}$