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Q. Water rises to a height $h$ in a capillary tube of crosssectional area $A$. The height to which water will rise in a capillary tube of cross-sectional area $4\, A$ will be

Mechanical Properties of Fluids

Solution:

$h=\frac{2 S \cos \theta}{r \rho g}$
Cross-sectional area increases four times, which means radius gets doubled.
So, $h^{\prime}=\frac{2 S}{2(r \rho g)}=\frac{h}{2}$