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Q. Water rises to a height 20 cm in a capillary tube of cross-sectional area A. If the cross-sectional area of tube is 4A, then the height to which water will rise in a tube is

Solution:

$h = \frac {2s\, cos \theta}{r \rho g}$
$\therefore h \propto \frac {1}{r} \propto \frac {1}{\sqrt {A}}$