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Q. Water of volume 2 L in a closed container is heated with a coil of 1 kW. While water is heated, the container loses energy at a rate of 160 J/s. In how much time will the temperature of water rise from 27$^{\circ}$C to 77$^{\circ}$C ? (Specific heat of water is $4.2 \,kJ/kg$ and that of the container is negligible).

JEE MainJEE Main 2014Thermal Properties of Matter

Solution:

$1000 - 160 = 840\, J/s$
$t-840=2\times4.2\times 10^{3}\times 50$
$t=\frac{500}{60}=8\,min\,20\,s.$