1. Tardigrade
  2. Question
  3. Physics
  4. Water falling from a 60 m high is to be used for generating electric power. If 9 × 105 kg of water falls per hour and half the gravitation potential energy can be converted into electric energy. How many 100 watt bulbs can be light ? ( g =10 m / s 2)

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Q. Water falling from a $60\, m$ high is to be used for generating electric power. If $9 \times 10^{5}\, kg$ of water falls per hour and half the gravitation potential energy can be converted into electric energy. How many $100$ watt bulbs can be light ? $\left( g =10 \,m / s ^{2}\right)$

Work, Energy and Power

Solution:

Power generated = Energy/sec
Acc. to question, $P=\frac{mgh}{2} \times \frac{1}{t}=\frac{1}{2} \times \frac{9 \times 10^{5} \times 10 \times 60}{60 \times 60}$
$\therefore P=7.5 \times 10^{5}=750000$ Watt
then no. of 100 Watt bulb can be light is $\frac{750000}{100}$
Bulb $=7500$