Question

Volume of $3\%$ solution of sodium carbonate necessary to neutralise a litre of $0.1\, N$ sulphuric acid

• A. 176.66 ml
• B. 156.6 ml
• C. 116.0 ml
• D. 196.1 ml

Answer 1

Answer: (A)

[a] Normality of $3 \% N a_{2} C O _{3}$
$N=\frac{3 \times 100}{53 \times 100}=0.566\, N$
For $H _{2} SO _{4}$ sol. $N _{1}=0.1, V _{1}=100\, mL$
For $Na _{2} CO _{3}$ sol. $N _{2}=0.566 . N _{2}$ ?
Now apply $N_{1} V_{1}=N_{2} V_{2}$
$V_{2}=\frac{N_{1} V_{1}}{N_{2}}=\frac{0.1 \times 100 mL }{0.566}$
$=176.66\, mL$