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  4. Volume of 0.1 M K2Cr2O7 required to oxidize 35 ml of 0.5 M FeSO4 solution is

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Q. Volume of 0.1 M $K_{2}Cr_{2}O_{7}$ required to oxidize 35 ml of 0.5 M $FeSO_{4}$ solution is

NTA AbhyasNTA Abhyas 2020Redox Reactions

Solution:

$K _{2} Cr _{2} O _{7}+6 FeSO _{4}+7 H _{2} SO _{4} \rightarrow K _{2} SO _{4}+ Cr _{2}\left( SO _{4}\right)_{3}$ $+3 Fe _{2}\left( SO _{4}\right)_{3}+7 H _{2} O$

For $K_{2}Cr_{2}O_{7},M=0.1M,n_{1}=1,V_{1}=?$

For $FeSO_{4},M=0.5M,n_{2}=6,V_{2}=35$ ml

$\frac{M_{1} V_{1}}{n_{1}}=\frac{M_{2} n_{2}}{n_{2}}$

$V_{1}=29.2$ ml