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  4. Visible spectrum extends from 400 nm (violet) to 750 nm (red). Hence frequency ratio is

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Q. Visible spectrum extends from $400\, nm$ (violet) to $750\, nm$ (red). Hence frequency ratio is

Structure of Atom

Solution:

$v_{1}=\frac{c}{\lambda_{1}}=\frac{c}{400 nm }$ ;

$v_{2}=\frac{c}{\lambda_{2}}=\frac{c}{750 nm }$

$\frac{v_{1}}{v_{2}}=\frac{c}{400} \times \frac{750}{c}=\frac{15}{8}$