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Q. Vibrating tuning fork of frequency $n$ is placed near the open end of a long cylindrical tube. The tube has a side opening and is fitted with a movable reflecting piston. As the piston is moved through $8.75\, cm$, the intensity of sound changes from a maximum to minimum. If the speed of sound is $350 \,m / s$. Then $n$ isPhysics Question Image

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Solution:

When the piston is moved through a distance of $8.75\, cm$, the path difference produced is $2 \times 8.75\, cm =17.5 \, cm$. This must be equal to $\frac{\lambda}{2}$ for maximum to change to minimum.
$\therefore \frac{\lambda}{2}=17.5\, cm $
$\Rightarrow \lambda=35 \, cm =0.35\, m$
So, $v=n \lambda \Rightarrow n=\frac{v}{\lambda}$
$=\frac{350}{0.35}=1000\, Hz$