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Q.
Velocity-time graph of a particle of mass $2\,kg$ moving in a straight line is as shown in figure. Work done by all forces on the particle is
Work, Energy and Power
Solution:
Initial velocity of particle, $v_{i}=20 \,ms ^{-1}$
Final velocity of the particle, $v_{f}=0$
According to work-energy theorem
$W_{\text {net }} =\Delta KE =K_{f}-K_{i} $
$=\frac{1}{2} m\left(v_{f}^{2}-v_{i}^{2}\right) $
$=\frac{1}{2} \times 2\left(0^{2}-20^{2}\right)=-400 \,J $
