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Q. Velocity and acceleration vectors of charged particle moving perpendicular to the direction of a magnetic field at a given instant of time are $\vec{ v }=2 \hat{ i }+c \hat{ j }$ and $\vec{ a }=3 \hat{ i }+4 \hat{ j }$ respectively. Then the value of $c$ is

EAMCETEAMCET 2007

Solution:

When a charged particle moves perpendicular to the magnetic field, it follows a circular path. On the circular path its velocity and acceleration will be at right angle to each other.
Given, $\vec{ v }=2 \hat{ i }+c \hat{ j }, \, \vec{ a }=3 \hat{ i }+4 \hat{ j }$
As $\vec{ v }$ and $\vec{ a }$ are perpendicular, hence
$\vec{ v } \cdot \vec{ a }=0$
$(2 \hat{ i }+c \hat{ j }) \cdot(3 \hat{ i }+4 \hat{ j })=0$
$\Rightarrow 6+4 c=0$
$\Rightarrow c=-1.5$