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  4. Variance of the numbers 3, 7, 10,18, 22 is equal to

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Q. Variance of the numbers 3, 7, 10,18, 22 is equal to

Statistics

Solution:

The mean of the given items
$ \bar{x} = \frac{3+7+10+18+22}{5} = 12$
Hence, variance $= \frac{1}{n} \sum (x_{i} - \bar{x} )^2$
$= \frac{1}{5}\left\{\left(3-12\right)^{2}+\left(7-12\right)^{2}+\left(10-12\right)^{2}+\left(18-12\right)^{2}+ \left(22-12\right)^{2} \right\}$
$= \frac{1}{5}\left\{81 + 25 + 4 + 36 + 100\right\}=\frac{246}{5} =49.2$