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Q. Vapour pressure of pure $A=100$ torr, moles $=2,$ vapour pressure of pure $B=80$ torr, moles $=3$ Total vapour pressure of mixture is

Solutions

Solution:

$ P_{\text {Total }} =p_{A} x_{A}+p_{B} x_{B} $

$=100 \times \frac{2}{5}+80 \times \frac{3}{5}=88 \text { torr }$