Tardigrade
Tardigrade - CET NEET JEE Exam App
Exams
Login
Signup
Tardigrade
Question
Chemistry
Vapour pressure of pure A=100 torr, moles =2, vapour pressure of pure B=80 torr, moles =3 Total vapour pressure of mixture is
Question Error Report
Question is incomplete/wrong
Question not belongs to this Chapter
Answer is wrong
Solution is wrong
Answer & Solution is not matching
Spelling mistake
Image missing
Website not working properly
Other (not listed above)
Error description
Thank you for reporting, we will resolve it shortly
Back to Question
Thank you for reporting, we will resolve it shortly
Q. Vapour pressure of pure $A=100$ torr, moles $=2,$ vapour pressure of pure $B=80$ torr, moles $=3$ Total vapour pressure of mixture is
Solutions
A
440 torr
24%
B
460 torr
10%
C
180 torr
20%
D
88 torr
46%
Solution:
$ P_{\text {Total }} =p_{A} x_{A}+p_{B} x_{B} $
$=100 \times \frac{2}{5}+80 \times \frac{3}{5}=88 \text { torr }$