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  3. Chemistry
  4. Vapour pressure of CCl4 at 25° C is 143 mm of Hg and 0.5 g of a non-volatile solute (mol. wt. = 65) is dissolved in 100 mL CCl4 . Find the vapour pressure of the solution. (Density of CCl4 =1.58 g text/cm3 ).

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Q. Vapour pressure of $ CC{{l}_{4}} $ at $ 25{}^\circ C $ is 143 mm of Hg and 0.5 g of a non-volatile solute (mol. wt. = 65) is dissolved in 100 mL $ CC{{l}_{4}}\,. $ Find the vapour pressure of the solution. (Density of $ CC{{l}_{4}}\,=1.58\,g\text{/}c{{m}^{3}} $ ).

CMC MedicalCMC Medical 2014

Solution:

Relative lowering in vapour pressure, $ \frac{p{}^\circ -{{p}_{s}}}{p{}^\circ }=\frac{w\times M}{m\times W} $ $ \frac{143-{{p}_{s}}}{143}=\frac{0.5}{65}\times \frac{154}{1.58\times 100} $ $ \left[ \begin{align} & \because Molecular\text{ }weight\text{ }of\,CC{{l}_{4}}=154 \\ & \,\,\,\,\,and\text{ }weight=density\times volume \\ \end{align} \right] $ $ 143-{{p}_{s}}=1.07 $ $ \Rightarrow $ $ {{p}_{s}}=141.93\,mm $