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  4. Vapour density of a volatile substance is 4 ( CH 4=1). Its molecular weight would ho.

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Q. Vapour density of a volatile substance is $4 \left( CH _{4}=1\right)$. Its molecular weight would ho.

JIPMERJIPMER 2003

Solution:

Actual vapour density of methane
$=\frac{\text { mol. wt }}{2}=\frac{16}{2}=8$
$\therefore $ vapour density of volatile substance $=8 \times 4=32$
Molecular weight of the substance $=32 \times 2=64$