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Q. Value of $\sin 10^{\circ}+\sin 20^{\circ}+\sin 30^{\circ}+\ldots \ldots+\sin 360^{\circ}$ is

Trigonometric Functions

Solution:

$\because \sin 190^{\circ}=\sin \left(180^{\circ}+10^{\circ}\right)=-\sin 10^{\circ}$
$\sin 200^{\circ}=-\sin 20^{\circ}$
$\sin 210^{\circ}=-\sin 30^{\circ}$
........................ .....................
$\sin 360^{\circ}=\sin 180^{\circ}=0$
$\therefore $ given expression $=0$