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Q. Using van der Waal's equation of state, calculate the pressure correction factor (in $atm\, L ^{2} mol ^{-2}$ ) for two moles of a gas confined in a $4$-litre flask that exert a pressure of $11 \,atm$ at $300 \,K , b=0.5\, L\, mol ^{-1}$ Use: $R=0.08$ litre atm $mol ^{-1} K ^{-1}$

States of Matter

Solution:

$\left(P+\frac{n^{2} a}{V^{2}}\right)(V-n b) =n R T $
$\Rightarrow \frac{n^{2} a}{V^{2}}=\frac{n R T}{V-n b}-P =\frac{2 \times 0.08 \times 300}{4-2 \times 0.5}-11 $
$=12-11=1 \,atm\, L ^{2} mol ^{-2} $