1. Tardigrade
  2. Question
  3. Chemistry
  4. Using the data given below find out the strongest reducing agent. E° Cr 2 O 4 / Cr 3+=1.33 V , E° Cl 2 / Cl -=1.36 V, E° MnO 4- / Mn 2+=1.51 V , E° Cr 3+ / Cr =-0.74 V

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Q. Using the data given below find out the strongest reducing agent.
$E^{\circ} Cr _{2} O _{4} / Cr ^{3+}=1.33\, V , E^{\circ} Cl _{2} / Cl ^{-}=1.36\, V$,
$E^{\circ} MnO _{4}^{-} / Mn ^{2+}=1.51 \,V , E^{\circ} Cr ^{3+} / Cr =-0.74 \,V$

AIIMSAIIMS 2013

Solution:

Strongest reducing agent is one which is oxidised most easily i.e., which has highest oxidation potential. $Cr / Cr ^{3+}$ has highest oxidation potential i.e., $(+0.74)$ so, it is oxidised most easily and therefore, it is the strongest reducing agent.