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Question
Chemistry
Uranium 92U238 decays into a stable isotope of:
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Q. Uranium $ {}_{92}{{U}^{238}} $ decays into a stable isotope of:
JIPMER
JIPMER 2000
A
$ Np $
B
$ Pb $
C
$ Rn $
D
$ Ra $
Solution:
The end product of $ {}_{92}{{U}^{238}} $ (4n +2) series is lead (Pb-206).