Thank you for reporting, we will resolve it shortly
Q.
Unlike $PbCl_{4}, PI_{4}$ and $PBr_{4}$ are not found because:
The p-Block Elements
Solution:
$Pb^{4+}$ has higher polarising power and $Br^{-}$ and $I^{-}$ being larger in size can easily give the electrons to $Pb^{4+}$, i.e., as compared to $Cl^{-}, Br^{-}$ and $I^{-}$ are good reducing agents