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Q. Unlike $PbCl_{4}, PI_{4}$ and $PBr_{4}$ are not found because:

The p-Block Elements

Solution:

$Pb^{4+}$ has higher polarising power and $Br^{-}$ and $I^{-}$ being larger in size can easily give the electrons to $Pb^{4+}$, i.e., as compared to $Cl^{-}, Br^{-}$ and $I^{-}$ are good reducing agents