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Q. $ \underset{x\to 0}{\mathop{\lim }}\,\left( \frac{{{a}^{x}}-{{b}^{x}}}{x} \right) $ is equal to:

KEAMKEAM 2000

Solution:

$ \underset{x\to 0}{\mathop{\lim }}\,\frac{{{a}^{x}}-{{b}^{x}}}{x}=\underset{x\to 0}{\mathop{\lim }}\,\frac{{{a}^{x}}-x}{x}-\underset{x\to 0}{\mathop{\lim }}\,\frac{{{b}^{x}}-1}{x} $