1. Tardigrade
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  3. Chemistry
  4. underset(A)3CH3COCH3 xrightarrow[-2H2O]HCl (CH3)2C = CH - CO - underset(B)CH = C(CH3)2 This polymer (B) is known as

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Q. $\underset{(A)}{3CH_3COCH_3} \xrightarrow[-2H_2O]{HCl}$
$(CH_3)_2C = CH - CO - \underset{(B)}{CH} = C(CH_3)_2$
This polymer (B) is known as

Aldehydes Ketones and Carboxylic Acids

Solution:

Correct answer is (a) phorone

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