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Q. Under isothermal condition, a gas at 300 K expands from 0.1 L to 0.25 L against a constant external pressure of 2 bar The work done by the gas is : [Given that 1Lbar= 100J)

NEETNEET 2019Thermodynamics

Solution:

$\therefore \; W_{irr} = - P_{ext } \Delta V$
= - 2 bar $\times$ (0.25 - 0.1) L
= - 2 $\times $ 0.15 L-bar
= - 0.30 L-bar
= - 0.30 $\times $ 100 J
= - 30 J