Question Error Report

Thank you for reporting, we will resolve it shortly

Back to Question

Q. - Uncertainty in position of a minute particle of mass $25\, g$ in space is $10^{-5} m$. The uncertainty in its velocity (in $ms ^{-1}$ ) is:

NEETNEET 2022

Solution:

$\Delta u =\frac{h}{4 \pi m . \Delta x}=\frac{6.626 \times 10^{-34}}{4 \times 3.14 \times 25 \times 10^{-3} \times 10^{-5}}$
$=2.1 \times 10^{-28} m \sec ^{-1}$