Question Error Report

Thank you for reporting, we will resolve it shortly

Back to Question

Q. Two waves having equation
$x_{1}=a \sin \left(\omega t-k x+\phi_{1}\right) $
$x_{2}=a \sin \left(\omega t-k x+\phi_{2}\right)$
If in the resultant wave the frequency and amplitude remain equal to amplitude of superimposing waves, the phase difference between them is

AIPMTAIPMT 2001Waves

Solution:

Resultant amplitude $=2 a(1+\cos \phi)= a$
$\therefore(1+\cos \phi)=1 / 2 ; \cos \phi=-\frac{1}{2} ; \phi=\frac{2 \pi}{3} \text {. }$