1. Tardigrade
  2. Question
  3. Physics
  4. Two very long, straight, parallel wires carry steady currents I and -I respectively. The distance between the wires is d. At a certain instant of time, a point charge q is at a point equidistant from the two wires, in the plane of the wires. Its instantaneous velocity v is perpendicular to the plane of wires. The magnitude of the force due to the magnetic field acting on the charge at this instant is

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Q. Two very long, straight, parallel wires carry steady currents $I$ and $-I$ respectively. The distance between the wires is $d$. At a certain instant of time, a point charge $q$ is at a point equidistant from the two wires, in the plane of the wires. Its instantaneous velocity $v$ is perpendicular to the plane of wires. The magnitude of the force due to the magnetic field acting on the charge at this instant is

Moving Charges and Magnetism

Solution:

Both $\vec{v}$ and $\vec{B}$ are perpendicular to plane of parallel wires.
$\therefore \vec{F}=q(\vec{v} \times \vec{B})=0$