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Q. Two vectors of same magnitude have a resultant equal to either, then the angle between the vectors will be:

EAMCETEAMCET 1996

Solution:

Given : $ \vec{A}=\vec{B}=\vec{R} $ Resultant, $ {{R}^{2}}={{A}^{2}}+{{B}^{2}}+2AB\cos \theta $ $ {{A}^{2}}={{A}^{2}}+{{A}^{2}}+2AA\cos \theta $ $ 1=1+1+2\cos \theta $ $ 2\cos \theta =1-2=-1 $ $ \cos \theta =-\frac{1}{2}=\cos {{120}^{o}} $ $ \theta ={{120}^{o}} $