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Q. Two vectors have magnitudes 3 and 5. If angle between them is 60$^{\circ}$, then the dot product of two vectors will be

Jharkhand CECEJharkhand CECE 2004Motion in a Plane

Solution:

Given A = 3. B = 5 and $\theta$ = 60$^{\circ}$
$ A . B = 3 \times 5 \times cos \, 60^\circ$
$ A . B = 15 \times \frac{1}{2} = 7.5$