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Physics
Two vectors have magnitudes 3 and 5. If angle between them is 60°, then the dot product of two vectors will be
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Q. Two vectors have magnitudes 3 and 5. If angle between them is 60$^{\circ}$, then the dot product of two vectors will be
Jharkhand CECE
Jharkhand CECE 2004
Motion in a Plane
A
7.5
65%
B
6.5
14%
C
8.4
13%
D
7.9
8%
Solution:
Given A = 3. B = 5 and $\theta$ = 60$^{\circ}$
$ A . B = 3 \times 5 \times cos \, 60^\circ$
$ A . B = 15 \times \frac{1}{2} = 7.5$