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Q. Two vectors $ \overrightarrow{A} $ and $ \overrightarrow{B} $ are such that $ |\overrightarrow{A}\times \overrightarrow{B}|=|\overrightarrow{A}.\overrightarrow{B}| $ then the angle between the two vectors is:

KEAMKEAM 2001

Solution:

$ |\overrightarrow{A}\times \overrightarrow{B}|=|\overrightarrow{A}.\overrightarrow{B}| $
$ \Rightarrow $ $ AB\sin \theta \hat{n}=AB\cos \theta \hat{n} $
$ \Rightarrow $ $ \tan \theta =1 $
$ \Rightarrow $ $ \theta =45{}^\circ $