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Q. Two tuning forks having frequencies $460\, Hz$ and $454\, Hz$ are tuned together. The time interval between successive maximum intensity will be

Waves

Solution:

Number of beats/second $=v_{1}-v_{2}=460-454=6$.
$\therefore \,\,\,$ Time interval between two successive beats $=\frac{1}{6} \,s$
This is the time interval between successive maximum intensity.