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  3. Chemistry
  4. Two substances A(t(1/2) = 5 m i n) and B(t(1/2) = 15 m i n) follow first order kinetics, are taken in such a way that initially [A]=4[B] . The time after which the concentration of both substances will be equal is:

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Q. Two substances $A\left(t_{\frac{1}{2}} = 5 m i n\right)$ and $B\left(t_{\frac{1}{2}} = 15 m i n\right)$ follow first order kinetics, are taken in such a way that initially $\left[A\right]=4\left[B\right]$ . The time after which the concentration of both substances will be equal is:

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