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  4. Two stones art thrown vertically upwards with the same velocity of 49m/s. If they are thrown one after the other with a time lapse of 3 second, height at which they collide is

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Q. Two stones art thrown vertically upwards with the same velocity of 49m/s. If they are thrown one after the other with a time lapse of 3 second, height at which they collide is

Motion in a Straight Line

Solution:

$s = ut - \frac{1}{2} gt^2 = u(t - 3) - \frac{1}{2} g(t - 3)^2$