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Q. Two spherical conducters $B$ and $C$ having equal radii and carrying equal charge in them repel each other with a force $F$ when kept at some distance. A third spherical conductors of same radii but uncharged is brought in contact with $B$ and brought in contact with $C$ and finally removed away from both. The new force of repulsion between $B$ and $C$ is :-

NTA AbhyasNTA Abhyas 2020

Solution:

Solution
$F=\frac{K Q^{2}}{r^{2}}$
$F^{'}=K\left(\frac{Q}{2}\right)\left(\frac{3 Q}{4}\right)$
$F^{'}=\frac{3}{8}F$