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  4. Two soap bubbles of radii r1 and r2 equal to 4 cm and 5 cm are touching each other over a common surface S1 and S2 shown in figure. Its radius will be :

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Q. Two soap bubbles of radii $r_1$ and $ r_2$ equal to $4\, cm$ and $5 \,cm$ are touching each other over a common surface $S_1$ and $S_2$ shown in figure. Its radius will be :

Haryana PMTHaryana PMT 2001

Solution:

Radius of curvature of common surface of double bubble
$r=\frac{r_{2} r_{1}}{r_{2}-r_{1}}=\frac{5 \times 4}{5-4}=20\, cm$