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Q. Two short magnets with their axes horizontal and perpendicular to the magnetic meridian are placed with their centres $40\, cm$ east and $50\, cm$ west of magnetic meridian. If the needle remains undeflected, the ratio of their magnetic moments $M_{1}: M_{2}$ is

Magnetism and Matter

Solution:

For null deflection, $\frac{M_{1}}{M_{2}}=\left(\frac{d_{1}}{d_{2}}\right)^{3}$
$=\left(\frac{40}{50}\right)^{3}=\frac{64}{125}$