Thank you for reporting, we will resolve it shortly
Q.
Two resistances $ R $ and $ 2R $ are connected in parallel in an electric circuit. The thermal energy developed in $ R $ and $ 2R $ are in the ratio
Given that, the two resistance $R$ and $2R$ are connected in parallel so the potential drop are equal for both
The thermal energy developed in a circuit is
$H=\frac{V^{2}t}{R}$
$\Rightarrow H \propto\frac{1}{R}$
$\Rightarrow \frac{H_{1}}{H_{2}}=\frac{R_{2}}{R_{1}}$
$\Rightarrow \frac{H_{1}}{H_{2}}=\frac{2R}{R}$
[Here, $R_{1} =R, R_{2} = 2R$]
or $H_{1}: H_{2}=2:1$
Hence, the correct answer is $(b)$
