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  4. Two putty balls of equal mass moving with equal velocity in mutually perpendicular directions, stick together after collision. If the balls were initially moving with a velocity of 45√2 m/sec each, the velocity of their combined mass after collision is (in m/sec).

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Q. Two putty balls of equal mass moving with equal velocity in mutually perpendicular directions, stick together after collision. If the balls were initially moving with a velocity of $45\sqrt{2}$ m/sec each, the velocity of their combined mass after collision is (in m/sec).

JIPMERJIPMER 2019Work, Energy and Power

Solution:

Initial momentum
$\vec{P} = m45\sqrt{2} \hat{i} + m45\sqrt{2} \hat{j}$
$\Rightarrow \quad\left|\vec{P}\right| = m\times90$
Final momentum 2m × V
By conservation of momentum
2m × V = m × 90
$\therefore $ V = 45 m/s

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