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Q. Two protons are kept at a separation of 40 $\mathring{A}$. $F_n$ is the nuclear force and $F_e$, is the electrostatic force between them. Then

KCETKCET 2008Nuclei

Solution:

$F_{n}$ is stronger than $F_{e} . F_{n}$ operates at very short range inside the nucleus as little as $10^{-15} m$ As in the given case two protons are kept at a separation of $40 \,\mathring{A} F_{n} << F_{e}$