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Q. Two projectiles $A$ and $B$ are thrown with the same speed but angles are $40^{\circ}$ and $50^{\circ}$ with the horizontal. Then

BITSATBITSAT 2010

Solution:

$T=\frac{2 u \sin \theta}{g}$, lesser is the value of, lesser is $\sin$ and hence lesser will be the time taken. Hence $A$ will fall earlier.