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  4. Two positive charges 2μ C and 10μ C are initially Separated by 10cm. The work done in bringing the charges 4cm closer

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Q. Two positive charges $2\mu\,C$ and 10$\mu\,C$ are initially Separated by 10cm. The work done in bringing the charges 4cm closer

Electrostatic Potential and Capacitance

Solution:

image
Work = change in P.E
$=k \cdot \frac{9_{1} 9_{2}}{r}$
change in $P E=k \cdot q_{1} q_{2}\left[\frac{1}{r_{1}}-\frac{1}{r_{2}}\right]$
$=k \cdot q_{1} q_{2}\left[\frac{1}{0.06}-\frac{1}{0.1}\right]$
$=9 \times 10^{9} \times 12 \times 10^{-6} \times 10 \times 10^{-6}[16.67-10]$
$=9 \times 10^{9} \times 12 \times 10^{-6} \times 10 \times 10^{-6} \times 6.67$
$=7.2\, J$