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Q. Two points $A$ and $B$ are located in diametrically opposite directions of a point charge of $+2 \, \mu C$ at distances $2 \,m$ and $1 \,m$ respectively from it. The potential difference between $A$ and $B$ is

Electrostatic Potential and Capacitance

Solution:

Here, $q=2 \, \mu C=2\times10^{-6}\,C$,
$r_{A}=2m, r_{B}=1\,m$
$\therefore V_{A}-V_{B}=\frac{q}{4\pi\varepsilon_{0}} \left[\frac{1}{r_{A}}-\frac{1}{r_{B}}\right]$
$=2 \times10^{-6}\times9\times10^{9}\left[\frac{1}{2}-\frac{1}{1}\right]V $
$=-9 \times10^{3}\, V$